test/string/LongestCommonSubsequence.test.cpp

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Last update: 2023-05-30 04:39:19+09:00
Problem: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_C

Depends on

LongestCommonSubsequence - LCS (lib/50-string/LongestCommonSubsequence.cpp)

Code

#define PROBLEM "http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_C"

#include <vector>
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
#include "../../lib/50-string/LongestCommonSubsequence.cpp"

int main() {
    cin.tie(0);ios::sync_with_stdio(false);
    int Q; cin >> Q;
    while(Q--) {
        string S,T; cin >> S >> T;
        cout << LongestCommonSubsequence(S,T).size() << endl;
    }
    return 0;
}

#line 1 "test/string/LongestCommonSubsequence.test.cpp"
#define PROBLEM "http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_10_C"

#include <vector>
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
#line 1 "lib/50-string/LongestCommonSubsequence.cpp"
/*
 * @title LongestCommonSubsequence - LCS
 * @docs md/string/LongestCommonSubsequence.md
 */
string LongestCommonSubsequence(const string& S, const string& T){
	int N = S.size(), M = T.size();
	vector<int> dp((N+1)*(M+1),0);
    for(size_t i = 0; i < N; i++) {
        for(size_t j = 0; j < M; j++) {
            dp[(i+1)*(M+1)+j+1] = (S[i] == T[j] ? dp[i*(M+1)+j] + 1 : max(dp[i*(M+1)+j + 1],dp[(i+1)*(M+1)+j]) );
        }
    }
    int a=N,b=M;
	string res = "";
	while(dp[a*(M+1)+b]>0) {
		if(S[a-1]==T[b-1]) res.push_back(S[a-1]),a--,b--;
		else (dp[(a-1)*(M+1)+b]>dp[a*(M+1)+b-1]?a:b)--;
	}
    reverse(res.begin(),res.end());
	return res;
}
#line 9 "test/string/LongestCommonSubsequence.test.cpp"

int main() {
    cin.tie(0);ios::sync_with_stdio(false);
    int Q; cin >> Q;
    while(Q--) {
        string S,T; cin >> S >> T;
        cout << LongestCommonSubsequence(S,T).size() << endl;
    }
    return 0;
}